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Oracle Database SQL Sample Questions (Q212-Q217):

NEW QUESTION # 212
View the exhibit and examine the description of the PRODUCT_INFORMATIONtable.

Which SQL statement would retrieve from the table the number of products having LIST_PRICEas NULL?
SELECT COUNT (DISTINCT list_price)

A. FROM product_information
WHERE list_price is NULL
B. FROM product_information
WHERE list_price i= NULL
SELECT COUNT (list_price)
C. FROM product_information
WHERE list_price is NULL
SELECT COUNT (NVL(list_price, 0))
D. FROM product_information
WHERE list_price is NULL
SELECT COUNT (list_price)

Answer: D

NEW QUESTION # 213
The first DROP operation is performed on PRODUCTS table using this command:
DROP TABLE products PURGE;
Then a FLASHBACK operation is performed using this command:
FLASHBACK TABLE products TO BEFORE DROP;
Which is true about the result of the FLASHBACK command?

A. It recovers only the table structure.
B. It recovers the table structure, data, and the indexes.
C. It recovers the table structure and data but not the related indexes.
D. It is not possible to recover the table structure, data, or the related indexes.

Answer: D

Explanation:
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_9003.htm

NEW QUESTION # 214
Examine the structure of the EMPLOYEEStable.

There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?

A. SELECT e.last_name, e.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
B. SELECT m.last_name, e.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123;
C. SELECT e.last_name, m.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123;
D. SELECT e.last_name, m.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123;

Answer: B

NEW QUESTION # 215
View the Exhibit and examine the structure of the PORDUCT_INFORMATION table. (Choose the best answer.)

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index?

A. SELECT UPPER(product_name)
FROM product_information;
B. SELECT product_id
FROM product_information
WHERE UPPER(product_name) IN ('LASERPRO', 'CABLE');
C. SELECT UPPER(product_name)
FROM product_information
WHERE product_id = 2254;
D. SELECT product_id, UPPER(product_name)
FROM product_information
WHERE UPPER(product_name) = 'LASERPRO' OR list_price > 1000;

Answer: B

NEW QUESTION # 216
Which three statements are true about dropping and unused columns in an Oracle database?

A. A column that is set to unused still counts towards the limit of 1000 columns per table.
B. A primary key column referenced by another column as a foreign key can be dropped if using the cascade option.
C. An unused column's space is reclaimed automatically when the row containing that column is next queried.
D. A drop column command can be rolled back.
E. An unused column's space is reclaimed automatically when the block containing that column is next queried.
F. Partition key columns cannot be dropped.

Answer: A,B,F

NEW QUESTION # 217
......

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Matt Clark Matt Clark

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